Distance from Peekskill to San Severino Marche
The shortest distance (air line) between Peekskill and San Severino Marche is 4,238.05 mi (6,820.48 km).
How far is Peekskill from San Severino Marche
Peekskill is located in New York, United States within 41° 17' 18.24" N -74° 4' 38.28" W (41.2884, -73.9227) coordinates. The local time in Peekskill is 01:18 (14.05.2025)
San Severino Marche is located in Macerata, Italy within 43° 13' 44.04" N 13° 10' 37.56" E (43.2289, 13.1771) coordinates. The local time in San Severino Marche is 07:18 (14.05.2025)
The calculated flying distance from San Severino Marche to San Severino Marche is 4,238.05 miles which is equal to 6,820.48 km.
Peekskill, New York, United States
Related Distances from Peekskill
San Severino Marche, Macerata, Italy