Distance from Peekskill to Sarospatak
The shortest distance (air line) between Peekskill and Sarospatak is 4,392.64 mi (7,069.27 km).
How far is Peekskill from Sarospatak
Peekskill is located in New York, United States within 41° 17' 18.24" N -74° 4' 38.28" W (41.2884, -73.9227) coordinates. The local time in Peekskill is 16:35 (06.05.2025)
Sarospatak is located in Borsod-Abaúj-Zemplén, Hungary within 48° 19' 8.4" N 21° 33' 59.04" E (48.3190, 21.5664) coordinates. The local time in Sarospatak is 22:35 (06.05.2025)
The calculated flying distance from Sarospatak to Sarospatak is 4,392.64 miles which is equal to 7,069.27 km.
Peekskill, New York, United States
Related Distances from Peekskill
Sarospatak, Borsod-Abaúj-Zemplén, Hungary