Distance from Peekskill to Sassenheim
The shortest distance (air line) between Peekskill and Sassenheim is 3,602.40 mi (5,797.50 km).
How far is Peekskill from Sassenheim
Peekskill is located in New York, United States within 41° 17' 18.24" N -74° 4' 38.28" W (41.2884, -73.9227) coordinates. The local time in Peekskill is 22:55 (16.05.2025)
Sassenheim is located in Agglomeratie Leiden en Bollenstreek, Netherlands within 52° 13' 32.88" N 4° 31' 21" E (52.2258, 4.5225) coordinates. The local time in Sassenheim is 04:55 (17.05.2025)
The calculated flying distance from Sassenheim to Sassenheim is 3,602.40 miles which is equal to 5,797.50 km.
Peekskill, New York, United States
Related Distances from Peekskill
Sassenheim, Agglomeratie Leiden en Bollenstreek, Netherlands