Distance from Peekskill to Savigny-le-Temple
The shortest distance (air line) between Peekskill and Savigny-le-Temple is 3,617.08 mi (5,821.13 km).
How far is Peekskill from Savigny-le-Temple
Peekskill is located in New York, United States within 41° 17' 18.24" N -74° 4' 38.28" W (41.2884, -73.9227) coordinates. The local time in Peekskill is 00:36 (25.04.2025)
Savigny-le-Temple is located in Seine-et-Marne, France within 48° 35' 2.76" N 2° 34' 59.52" E (48.5841, 2.5832) coordinates. The local time in Savigny-le-Temple is 06:36 (25.04.2025)
The calculated flying distance from Savigny-le-Temple to Savigny-le-Temple is 3,617.08 miles which is equal to 5,821.13 km.
Peekskill, New York, United States
Related Distances from Peekskill
Savigny-le-Temple, Seine-et-Marne, France