Distance from Peekskill to Scherpenheuvel
The shortest distance (air line) between Peekskill and Scherpenheuvel is 3,651.46 mi (5,876.46 km).
How far is Peekskill from Scherpenheuvel
Peekskill is located in New York, United States within 41° 17' 18.24" N -74° 4' 38.28" W (41.2884, -73.9227) coordinates. The local time in Peekskill is 16:09 (20.04.2025)
Scherpenheuvel is located in Arr. Leuven, Belgium within 51° 0' 37.08" N 4° 58' 22.08" E (51.0103, 4.9728) coordinates. The local time in Scherpenheuvel is 22:09 (20.04.2025)
The calculated flying distance from Scherpenheuvel to Scherpenheuvel is 3,651.46 miles which is equal to 5,876.46 km.
Peekskill, New York, United States
Related Distances from Peekskill
Scherpenheuvel, Arr. Leuven, Belgium