Distance from Peekskill to Sendenhorst
The shortest distance (air line) between Peekskill and Sendenhorst is 3,742.37 mi (6,022.76 km).
How far is Peekskill from Sendenhorst
Peekskill is located in New York, United States within 41° 17' 18.24" N -74° 4' 38.28" W (41.2884, -73.9227) coordinates. The local time in Peekskill is 05:46 (01.05.2025)
Sendenhorst is located in Warendorf, Germany within 51° 50' 38.04" N 7° 49' 40.08" E (51.8439, 7.8278) coordinates. The local time in Sendenhorst is 11:46 (01.05.2025)
The calculated flying distance from Sendenhorst to Sendenhorst is 3,742.37 miles which is equal to 6,022.76 km.
Peekskill, New York, United States
Related Distances from Peekskill
Sendenhorst, Warendorf, Germany