Distance from Peekskill to Sever do Vouga
The shortest distance (air line) between Peekskill and Sever do Vouga is 3,332.13 mi (5,362.55 km).
How far is Peekskill from Sever do Vouga
Peekskill is located in New York, United States within 41° 17' 18.24" N -74° 4' 38.28" W (41.2884, -73.9227) coordinates. The local time in Peekskill is 18:02 (19.05.2025)
Sever do Vouga is located in Região de Aveiro, Portugal within 40° 43' 59.88" N -9° 37' 59.88" W (40.7333, -8.3667) coordinates. The local time in Sever do Vouga is 23:02 (19.05.2025)
The calculated flying distance from Sever do Vouga to Sever do Vouga is 3,332.13 miles which is equal to 5,362.55 km.
Peekskill, New York, United States
Related Distances from Peekskill
Sever do Vouga, Região de Aveiro, Portugal