Distance from Peekskill to Sint-Amandsberg
The shortest distance (air line) between Peekskill and Sint-Amandsberg is 3,601.02 mi (5,795.28 km).
How far is Peekskill from Sint-Amandsberg
Peekskill is located in New York, United States within 41° 17' 18.24" N -74° 4' 38.28" W (41.2884, -73.9227) coordinates. The local time in Peekskill is 16:22 (20.04.2025)
Sint-Amandsberg is located in Arr. Gent, Belgium within 51° 3' 14.04" N 3° 44' 57.12" E (51.0539, 3.7492) coordinates. The local time in Sint-Amandsberg is 22:22 (20.04.2025)
The calculated flying distance from Sint-Amandsberg to Sint-Amandsberg is 3,601.02 miles which is equal to 5,795.28 km.
Peekskill, New York, United States
Related Distances from Peekskill
Sint-Amandsberg, Arr. Gent, Belgium