Distance from Peekskill to Sint-Genesius-Rode
The shortest distance (air line) between Peekskill and Sint-Genesius-Rode is 3,633.11 mi (5,846.93 km).
How far is Peekskill from Sint-Genesius-Rode
Peekskill is located in New York, United States within 41° 17' 18.24" N -74° 4' 38.28" W (41.2884, -73.9227) coordinates. The local time in Peekskill is 17:46 (20.04.2025)
Sint-Genesius-Rode is located in Arr. Halle-Vilvoorde, Belgium within 50° 44' 42" N 4° 20' 47.04" E (50.7450, 4.3464) coordinates. The local time in Sint-Genesius-Rode is 23:46 (20.04.2025)
The calculated flying distance from Sint-Genesius-Rode to Sint-Genesius-Rode is 3,633.11 miles which is equal to 5,846.93 km.
Peekskill, New York, United States
Related Distances from Peekskill
Sint-Genesius-Rode, Arr. Halle-Vilvoorde, Belgium