Distance from Peekskill to Sint-Katelijne-Waver
The shortest distance (air line) between Peekskill and Sint-Katelijne-Waver is 3,632.31 mi (5,845.63 km).
How far is Peekskill from Sint-Katelijne-Waver
Peekskill is located in New York, United States within 41° 17' 18.24" N -74° 4' 38.28" W (41.2884, -73.9227) coordinates. The local time in Peekskill is 14:59 (20.04.2025)
Sint-Katelijne-Waver is located in Arr. Mechelen, Belgium within 51° 4' 0.12" N 4° 31' 59.88" E (51.0667, 4.5333) coordinates. The local time in Sint-Katelijne-Waver is 20:59 (20.04.2025)
The calculated flying distance from Sint-Katelijne-Waver to Sint-Katelijne-Waver is 3,632.31 miles which is equal to 5,845.63 km.
Peekskill, New York, United States
Related Distances from Peekskill
Sint-Katelijne-Waver, Arr. Mechelen, Belgium