Distance from Peekskill to Sint-Martens-Lennik
The shortest distance (air line) between Peekskill and Sint-Martens-Lennik is 3,623.73 mi (5,831.84 km).
How far is Peekskill from Sint-Martens-Lennik
Peekskill is located in New York, United States within 41° 17' 18.24" N -74° 4' 38.28" W (41.2884, -73.9227) coordinates. The local time in Peekskill is 14:40 (20.04.2025)
Sint-Martens-Lennik is located in Arr. Halle-Vilvoorde, Belgium within 50° 47' 60" N 4° 9' 0" E (50.8000, 4.1500) coordinates. The local time in Sint-Martens-Lennik is 20:40 (20.04.2025)
The calculated flying distance from Sint-Martens-Lennik to Sint-Martens-Lennik is 3,623.73 miles which is equal to 5,831.84 km.
Peekskill, New York, United States
Related Distances from Peekskill
Sint-Martens-Lennik, Arr. Halle-Vilvoorde, Belgium