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      Distance from Peekskill to Sint-Pieters-Leeuw

      The shortest distance (air line) between Peekskill and Sint-Pieters-Leeuw is 3,628.22 mi (5,839.05 km).

      How far is Peekskill from Sint-Pieters-Leeuw

      Peekskill is located in New York, United States within 41° 17' 18.24" N -74° 4' 38.28" W (41.2884, -73.9227) coordinates. The local time in Peekskill is 14:58 (20.04.2025)

      Sint-Pieters-Leeuw is located in Arr. Halle-Vilvoorde, Belgium within 50° 46' 59.88" N 4° 15' 0" E (50.7833, 4.2500) coordinates. The local time in Sint-Pieters-Leeuw is 20:58 (20.04.2025)

      The calculated flying distance from Sint-Pieters-Leeuw to Sint-Pieters-Leeuw is 3,628.22 miles which is equal to 5,839.05 km.

      Peekskill, New York, United States

      Related Distances from Peekskill

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      Sint-Pieters-Leeuw, Arr. Halle-Vilvoorde, Belgium

      Related Distances to Sint-Pieters-Leeuw