Distance from Peekskill to Tomaz pri Ormozu
The shortest distance (air line) between Peekskill and Tomaz pri Ormozu is 4,243.25 mi (6,828.86 km).
How far is Peekskill from Tomaz pri Ormozu
Peekskill is located in New York, United States within 41° 17' 18.24" N -74° 4' 38.28" W (41.2884, -73.9227) coordinates. The local time in Peekskill is 08:54 (22.05.2025)
Tomaz pri Ormozu is located in Podravska, Slovenia within 46° 28' 59.88" N 16° 4' 45.84" E (46.4833, 16.0794) coordinates. The local time in Tomaz pri Ormozu is 14:54 (22.05.2025)
The calculated flying distance from Tomaz pri Ormozu to Tomaz pri Ormozu is 4,243.25 miles which is equal to 6,828.86 km.
Peekskill, New York, United States
Related Distances from Peekskill
Tomaz pri Ormozu, Podravska, Slovenia