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      Distance from Peekskill to Villanueva de la Serena

      The shortest distance (air line) between Peekskill and Villanueva de la Serena is 3,506.76 mi (5,643.59 km).

      How far is Peekskill from Villanueva de la Serena

      Peekskill is located in New York, United States within 41° 17' 18.24" N -74° 4' 38.28" W (41.2884, -73.9227) coordinates. The local time in Peekskill is 21:41 (27.05.2025)

      Villanueva de la Serena is located in Badajoz, Spain within 38° 58' 0.12" N -6° 12' 0" W (38.9667, -5.8000) coordinates. The local time in Villanueva de la Serena is 03:41 (28.05.2025)

      The calculated flying distance from Villanueva de la Serena to Villanueva de la Serena is 3,506.76 miles which is equal to 5,643.59 km.

      Peekskill, New York, United States

      Related Distances from Peekskill

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      Peekskill to Dallas (Texas)1,384.26 mi (2,227.74 km)
      Peekskill to Houston (Texas)1,438.74 mi (2,315.43 km)
      Peekskill to Denver (Colorado)1,620.44 mi (2,607.84 km)
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      Peekskill to Portland (Oregon)2,425.40 mi (3,903.30 km)
      Peekskill to San Diego (California)2,426.16 mi (3,904.52 km)
      Peekskill to Los Angeles (California)2,454.25 mi (3,949.73 km)
      Peekskill to San Francisco (California)2,563.92 mi (4,126.24 km)
      Peekskill to Queens (New York)37.78 mi (60.80 km)
      Peekskill to New York (New York)41.05 mi (66.06 km)
      Peekskill to Brooklyn (New York)44.12 mi (71.01 km)
      Peekskill to Baltimore (Maryland)197.21 mi (317.37 km)
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      Villanueva de la Serena, Badajoz, Spain

      Related Distances to Villanueva de la Serena