Distance from Peekskill to s-Heerenberg
The shortest distance (air line) between Peekskill and s-Heerenberg is 3,679.34 mi (5,921.33 km).
How far is Peekskill from s-Heerenberg
Peekskill is located in New York, United States within 41° 17' 18.24" N -74° 4' 38.28" W (41.2884, -73.9227) coordinates. The local time in Peekskill is 22:55 (16.05.2025)
s-Heerenberg is located in Achterhoek, Netherlands within 51° 52' 35.04" N 6° 14' 44.88" E (51.8764, 6.2458) coordinates. The local time in s-Heerenberg is 04:55 (17.05.2025)
The calculated flying distance from s-Heerenberg to s-Heerenberg is 3,679.34 miles which is equal to 5,921.33 km.
Peekskill, New York, United States
Related Distances from Peekskill
s-Heerenberg, Achterhoek, Netherlands