Distance from Peso da Regua to Aleksandrow Kujawski
The shortest distance (air line) between Peso da Regua and Aleksandrow Kujawski is 1,473.20 mi (2,370.89 km).
How far is Peso da Regua from Aleksandrow Kujawski
Peso da Regua is located in Douro, Portugal within 41° 9' 55.08" N -8° 13' 24.96" W (41.1653, -7.7764) coordinates. The local time in Peso da Regua is 08:18 (24.02.2025)
Aleksandrow Kujawski is located in Włocławski, Poland within 52° 52' 36.12" N 18° 41' 36.96" E (52.8767, 18.6936) coordinates. The local time in Aleksandrow Kujawski is 09:18 (24.02.2025)
The calculated flying distance from Aleksandrow Kujawski to Aleksandrow Kujawski is 1,473.20 miles which is equal to 2,370.89 km.
Peso da Regua, Douro, Portugal
Related Distances from Peso da Regua
Aleksandrow Kujawski, Włocławski, Poland