Distance from Peso da Regua to Aleksandrow Lodzki
The shortest distance (air line) between Peso da Regua and Aleksandrow Lodzki is 1,471.10 mi (2,367.51 km).
How far is Peso da Regua from Aleksandrow Lodzki
Peso da Regua is located in Douro, Portugal within 41° 9' 55.08" N -8° 13' 24.96" W (41.1653, -7.7764) coordinates. The local time in Peso da Regua is 12:14 (24.02.2025)
Aleksandrow Lodzki is located in Łódzki, Poland within 51° 49' 9.84" N 19° 18' 14.04" E (51.8194, 19.3039) coordinates. The local time in Aleksandrow Lodzki is 13:14 (24.02.2025)
The calculated flying distance from Aleksandrow Lodzki to Aleksandrow Lodzki is 1,471.10 miles which is equal to 2,367.51 km.
Peso da Regua, Douro, Portugal
Related Distances from Peso da Regua
Aleksandrow Lodzki, Łódzki, Poland