Distance from Peso da Regua to Tomaszow Lubelski
The shortest distance (air line) between Peso da Regua and Tomaszow Lubelski is 1,618.36 mi (2,604.49 km).
How far is Peso da Regua from Tomaszow Lubelski
Peso da Regua is located in Douro, Portugal within 41° 9' 55.08" N -8° 13' 24.96" W (41.1653, -7.7764) coordinates. The local time in Peso da Regua is 09:40 (25.02.2025)
Tomaszow Lubelski is located in Chełmsko-zamojski, Poland within 50° 27' 0" N 23° 25' 0.12" E (50.4500, 23.4167) coordinates. The local time in Tomaszow Lubelski is 10:40 (25.02.2025)
The calculated flying distance from Tomaszow Lubelski to Tomaszow Lubelski is 1,618.36 miles which is equal to 2,604.49 km.
Peso da Regua, Douro, Portugal
Related Distances from Peso da Regua
Tomaszow Lubelski, Chełmsko-zamojski, Poland