Distance from Peso da Regua to Vetraz-Monthoux
The shortest distance (air line) between Peso da Regua and Vetraz-Monthoux is 780.50 mi (1,256.10 km).
How far is Peso da Regua from Vetraz-Monthoux
Peso da Regua is located in Douro, Portugal within 41° 9' 55.08" N -8° 13' 24.96" W (41.1653, -7.7764) coordinates. The local time in Peso da Regua is 09:51 (27.01.2025)
Vetraz-Monthoux is located in Haute-Savoie, France within 46° 10' 27.12" N 6° 15' 18" E (46.1742, 6.2550) coordinates. The local time in Vetraz-Monthoux is 10:51 (27.01.2025)
The calculated flying distance from Vetraz-Monthoux to Vetraz-Monthoux is 780.50 miles which is equal to 1,256.10 km.
Peso da Regua, Douro, Portugal
Related Distances from Peso da Regua
Vetraz-Monthoux, Haute-Savoie, France