Distance from Petersburg to Anguillara Sabazia
The shortest distance (air line) between Petersburg and Anguillara Sabazia is 4,551.31 mi (7,324.63 km).
How far is Petersburg from Anguillara Sabazia
Petersburg is located in Virginia, United States within 37° 12' 15.48" N -78° 36' 31.32" W (37.2043, -77.3913) coordinates. The local time in Petersburg is 14:57 (24.02.2025)
Anguillara Sabazia is located in Roma, Italy within 42° 4' 59.88" N 12° 16' 0.12" E (42.0833, 12.2667) coordinates. The local time in Anguillara Sabazia is 20:57 (24.02.2025)
The calculated flying distance from Anguillara Sabazia to Anguillara Sabazia is 4,551.31 miles which is equal to 7,324.63 km.
Petersburg, Virginia, United States
Related Distances from Petersburg
Anguillara Sabazia, Roma, Italy