Distance from Petersburg to Aubergenville
The shortest distance (air line) between Petersburg and Aubergenville is 3,895.71 mi (6,269.54 km).
How far is Petersburg from Aubergenville
Petersburg is located in Virginia, United States within 37° 12' 15.48" N -78° 36' 31.32" W (37.2043, -77.3913) coordinates. The local time in Petersburg is 09:11 (11.02.2025)
Aubergenville is located in Yvelines, France within 48° 57' 29.88" N 1° 51' 18" E (48.9583, 1.8550) coordinates. The local time in Aubergenville is 15:11 (11.02.2025)
The calculated flying distance from Aubergenville to Aubergenville is 3,895.71 miles which is equal to 6,269.54 km.
Petersburg, Virginia, United States
Related Distances from Petersburg
Aubergenville, Yvelines, France