Distance from Petersburg to Bad Sassendorf
The shortest distance (air line) between Petersburg and Bad Sassendorf is 4,090.12 mi (6,582.41 km).
How far is Petersburg from Bad Sassendorf
Petersburg is located in Virginia, United States within 37° 12' 15.48" N -78° 36' 31.32" W (37.2043, -77.3913) coordinates. The local time in Petersburg is 17:03 (08.02.2025)
Bad Sassendorf is located in Soest, Germany within 51° 34' 59.16" N 8° 10' 0.12" E (51.5831, 8.1667) coordinates. The local time in Bad Sassendorf is 23:03 (08.02.2025)
The calculated flying distance from Bad Sassendorf to Bad Sassendorf is 4,090.12 miles which is equal to 6,582.41 km.
Petersburg, Virginia, United States
Related Distances from Petersburg
Bad Sassendorf, Soest, Germany