Distance from Petersburg to Bad Segeberg
The shortest distance (air line) between Petersburg and Bad Segeberg is 4,111.58 mi (6,616.96 km).
How far is Petersburg from Bad Segeberg
Petersburg is located in Virginia, United States within 37° 12' 15.48" N -78° 36' 31.32" W (37.2043, -77.3913) coordinates. The local time in Petersburg is 20:44 (12.02.2025)
Bad Segeberg is located in Segeberg, Germany within 53° 55' 0.12" N 10° 19' 0.12" E (53.9167, 10.3167) coordinates. The local time in Bad Segeberg is 02:44 (13.02.2025)
The calculated flying distance from Bad Segeberg to Bad Segeberg is 4,111.58 miles which is equal to 6,616.96 km.
Petersburg, Virginia, United States
Related Distances from Petersburg
Bad Segeberg, Segeberg, Germany