Distance from Petersburg to Bagnols-sur-Ceze
The shortest distance (air line) between Petersburg and Bagnols-sur-Ceze is 4,142.53 mi (6,666.76 km).
How far is Petersburg from Bagnols-sur-Ceze
Petersburg is located in Virginia, United States within 37° 12' 15.48" N -78° 36' 31.32" W (37.2043, -77.3913) coordinates. The local time in Petersburg is 09:13 (06.02.2025)
Bagnols-sur-Ceze is located in Gard, France within 44° 9' 45" N 4° 37' 12" E (44.1625, 4.6200) coordinates. The local time in Bagnols-sur-Ceze is 15:13 (06.02.2025)
The calculated flying distance from Bagnols-sur-Ceze to Bagnols-sur-Ceze is 4,142.53 miles which is equal to 6,666.76 km.
Petersburg, Virginia, United States
Related Distances from Petersburg
Bagnols-sur-Ceze, Gard, France