Distance from Petersburg to Begijnendijk
The shortest distance (air line) between Petersburg and Begijnendijk is 3,968.47 mi (6,386.63 km).
How far is Petersburg from Begijnendijk
Petersburg is located in Virginia, United States within 37° 12' 15.48" N -78° 36' 31.32" W (37.2043, -77.3913) coordinates. The local time in Petersburg is 16:04 (09.02.2025)
Begijnendijk is located in Arr. Leuven, Belgium within 51° 1' 6.96" N 4° 47' 6" E (51.0186, 4.7850) coordinates. The local time in Begijnendijk is 22:04 (09.02.2025)
The calculated flying distance from Begijnendijk to Begijnendijk is 3,968.47 miles which is equal to 6,386.63 km.
Petersburg, Virginia, United States
Related Distances from Petersburg
Begijnendijk, Arr. Leuven, Belgium