Distance from Petersburg to Bouguenais
The shortest distance (air line) between Petersburg and Bouguenais is 3,785.60 mi (6,092.34 km).
How far is Petersburg from Bouguenais
Petersburg is located in Virginia, United States within 37° 12' 15.48" N -78° 36' 31.32" W (37.2043, -77.3913) coordinates. The local time in Petersburg is 11:51 (06.02.2025)
Bouguenais is located in Loire-Atlantique, France within 47° 10' 39" N -2° 22' 42.96" W (47.1775, -1.6214) coordinates. The local time in Bouguenais is 17:51 (06.02.2025)
The calculated flying distance from Bouguenais to Bouguenais is 3,785.60 miles which is equal to 6,092.34 km.
Petersburg, Virginia, United States
Related Distances from Petersburg
Bouguenais, Loire-Atlantique, France