Distance from Petersburg to Buggenhout
The shortest distance (air line) between Petersburg and Buggenhout is 3,945.08 mi (6,348.99 km).
How far is Petersburg from Buggenhout
Petersburg is located in Virginia, United States within 37° 12' 15.48" N -78° 36' 31.32" W (37.2043, -77.3913) coordinates. The local time in Petersburg is 08:53 (04.02.2025)
Buggenhout is located in Arr. Dendermonde, Belgium within 51° 0' 0" N 4° 12' 0" E (51.0000, 4.2000) coordinates. The local time in Buggenhout is 14:53 (04.02.2025)
The calculated flying distance from Buggenhout to Buggenhout is 3,945.08 miles which is equal to 6,348.99 km.
Petersburg, Virginia, United States
Related Distances from Petersburg
Buggenhout, Arr. Dendermonde, Belgium