Distance from Petersburg to Diepenbeek
The shortest distance (air line) between Petersburg and Diepenbeek is 3,996.93 mi (6,432.44 km).
How far is Petersburg from Diepenbeek
Petersburg is located in Virginia, United States within 37° 12' 15.48" N -78° 36' 31.32" W (37.2043, -77.3913) coordinates. The local time in Petersburg is 07:59 (10.02.2025)
Diepenbeek is located in Arr. Hasselt, Belgium within 50° 54' 25.92" N 5° 25' 3" E (50.9072, 5.4175) coordinates. The local time in Diepenbeek is 13:59 (10.02.2025)
The calculated flying distance from Diepenbeek to Diepenbeek is 3,996.93 miles which is equal to 6,432.44 km.
Petersburg, Virginia, United States
Related Distances from Petersburg
Diepenbeek, Arr. Hasselt, Belgium