Distance from Petersburg to Fontainebleau
The shortest distance (air line) between Petersburg and Fontainebleau is 3,945.15 mi (6,349.11 km).
How far is Petersburg from Fontainebleau
Petersburg is located in Virginia, United States within 37° 12' 15.48" N -78° 36' 31.32" W (37.2043, -77.3913) coordinates. The local time in Petersburg is 23:13 (06.02.2025)
Fontainebleau is located in Seine-et-Marne, France within 48° 24' 32.04" N 2° 42' 6.12" E (48.4089, 2.7017) coordinates. The local time in Fontainebleau is 05:13 (07.02.2025)
The calculated flying distance from Fontainebleau to Fontainebleau is 3,945.15 miles which is equal to 6,349.11 km.
Petersburg, Virginia, United States
Related Distances from Petersburg
Fontainebleau, Seine-et-Marne, France