Distance from Petersburg to Heist-op-den-Berg
The shortest distance (air line) between Petersburg and Heist-op-den-Berg is 3,964.12 mi (6,379.64 km).
How far is Petersburg from Heist-op-den-Berg
Petersburg is located in Virginia, United States within 37° 12' 15.48" N -78° 36' 31.32" W (37.2043, -77.3913) coordinates. The local time in Petersburg is 13:46 (04.02.2025)
Heist-op-den-Berg is located in Arr. Mechelen, Belgium within 51° 4' 59.88" N 4° 43' 0.12" E (51.0833, 4.7167) coordinates. The local time in Heist-op-den-Berg is 19:46 (04.02.2025)
The calculated flying distance from Heist-op-den-Berg to Heist-op-den-Berg is 3,964.12 miles which is equal to 6,379.64 km.
Petersburg, Virginia, United States
Related Distances from Petersburg
Heist-op-den-Berg, Arr. Mechelen, Belgium