Distance from Petersburg to Hodmezovasarhely
The shortest distance (air line) between Petersburg and Hodmezovasarhely is 4,741.62 mi (7,630.90 km).
How far is Petersburg from Hodmezovasarhely
Petersburg is located in Virginia, United States within 37° 12' 15.48" N -78° 36' 31.32" W (37.2043, -77.3913) coordinates. The local time in Petersburg is 17:56 (23.02.2025)
Hodmezovasarhely is located in Csongrád, Hungary within 46° 25' 49.44" N 20° 19' 7.68" E (46.4304, 20.3188) coordinates. The local time in Hodmezovasarhely is 23:56 (23.02.2025)
The calculated flying distance from Hodmezovasarhely to Hodmezovasarhely is 4,741.62 miles which is equal to 7,630.90 km.
Petersburg, Virginia, United States
Related Distances from Petersburg
Hodmezovasarhely, Csongrád, Hungary