Distance from Petersburg to Hohenstein-Ernstthal
The shortest distance (air line) between Petersburg and Hohenstein-Ernstthal is 4,292.05 mi (6,907.38 km).
How far is Petersburg from Hohenstein-Ernstthal
Petersburg is located in Virginia, United States within 37° 12' 15.48" N -78° 36' 31.32" W (37.2043, -77.3913) coordinates. The local time in Petersburg is 23:10 (11.02.2025)
Hohenstein-Ernstthal is located in Zwickau, Germany within 50° 47' 60" N 12° 43' 0.12" E (50.8000, 12.7167) coordinates. The local time in Hohenstein-Ernstthal is 05:10 (12.02.2025)
The calculated flying distance from Hohenstein-Ernstthal to Hohenstein-Ernstthal is 4,292.05 miles which is equal to 6,907.38 km.
Petersburg, Virginia, United States
Related Distances from Petersburg
Hohenstein-Ernstthal, Zwickau, Germany