Distance from Petersburg to La Puebla del Rio
The shortest distance (air line) between Petersburg and La Puebla del Rio is 3,822.55 mi (6,151.80 km).
How far is Petersburg from La Puebla del Rio
Petersburg is located in Virginia, United States within 37° 12' 15.48" N -78° 36' 31.32" W (37.2043, -77.3913) coordinates. The local time in Petersburg is 03:16 (12.03.2025)
La Puebla del Rio is located in Sevilla, Spain within 37° 16' 0.12" N -7° 57' 0" W (37.2667, -6.0500) coordinates. The local time in La Puebla del Rio is 09:16 (12.03.2025)
The calculated flying distance from La Puebla del Rio to La Puebla del Rio is 3,822.55 miles which is equal to 6,151.80 km.
Petersburg, Virginia, United States
Related Distances from Petersburg
La Puebla del Rio, Sevilla, Spain