Distance from Petersburg to Maxhutte-Haidhof
The shortest distance (air line) between Petersburg and Maxhutte-Haidhof is 4,315.67 mi (6,945.40 km).
How far is Petersburg from Maxhutte-Haidhof
Petersburg is located in Virginia, United States within 37° 12' 15.48" N -78° 36' 31.32" W (37.2043, -77.3913) coordinates. The local time in Petersburg is 00:06 (15.02.2025)
Maxhutte-Haidhof is located in Schwandorf, Germany within 49° 12' 0" N 12° 5' 60" E (49.2000, 12.1000) coordinates. The local time in Maxhutte-Haidhof is 06:06 (15.02.2025)
The calculated flying distance from Maxhutte-Haidhof to Maxhutte-Haidhof is 4,315.67 miles which is equal to 6,945.40 km.
Petersburg, Virginia, United States
Related Distances from Petersburg
Maxhutte-Haidhof, Schwandorf, Germany