Distance from Petersburg to Montceau-les-Mines
The shortest distance (air line) between Petersburg and Montceau-les-Mines is 4,062.12 mi (6,537.36 km).
How far is Petersburg from Montceau-les-Mines
Petersburg is located in Virginia, United States within 37° 12' 15.48" N -78° 36' 31.32" W (37.2043, -77.3913) coordinates. The local time in Petersburg is 14:06 (07.02.2025)
Montceau-les-Mines is located in Saône-et-Loire, France within 46° 40' 0.84" N 4° 22' 8.04" E (46.6669, 4.3689) coordinates. The local time in Montceau-les-Mines is 20:06 (07.02.2025)
The calculated flying distance from Montceau-les-Mines to Montceau-les-Mines is 4,062.12 miles which is equal to 6,537.36 km.
Petersburg, Virginia, United States
Related Distances from Petersburg
Montceau-les-Mines, Saône-et-Loire, France