Distance from Petersburg to Montigny-en-Gohelle
The shortest distance (air line) between Petersburg and Montigny-en-Gohelle is 3,906.35 mi (6,286.67 km).
How far is Petersburg from Montigny-en-Gohelle
Petersburg is located in Virginia, United States within 37° 12' 15.48" N -78° 36' 31.32" W (37.2043, -77.3913) coordinates. The local time in Petersburg is 13:50 (07.02.2025)
Montigny-en-Gohelle is located in Pas-de-Calais, France within 50° 25' 40.08" N 2° 55' 46.92" E (50.4278, 2.9297) coordinates. The local time in Montigny-en-Gohelle is 19:50 (07.02.2025)
The calculated flying distance from Montigny-en-Gohelle to Montigny-en-Gohelle is 3,906.35 miles which is equal to 6,286.67 km.
Petersburg, Virginia, United States
Related Distances from Petersburg
Montigny-en-Gohelle, Pas-de-Calais, France