Distance from Petersburg to Naujoji Akmene
The shortest distance (air line) between Petersburg and Naujoji Akmene is 4,484.02 mi (7,216.34 km).
How far is Petersburg from Naujoji Akmene
Petersburg is located in Virginia, United States within 37° 12' 15.48" N -78° 36' 31.32" W (37.2043, -77.3913) coordinates. The local time in Petersburg is 05:42 (28.02.2025)
Naujoji Akmene is located in Šiaulių apskritis, Lithuania within 56° 19' 0.12" N 22° 53' 60" E (56.3167, 22.9000) coordinates. The local time in Naujoji Akmene is 12:42 (28.02.2025)
The calculated flying distance from Naujoji Akmene to Naujoji Akmene is 4,484.02 miles which is equal to 7,216.34 km.
Petersburg, Virginia, United States
Related Distances from Petersburg
Naujoji Akmene, Šiaulių apskritis, Lithuania