Distance from Petersburg to Opglabbeek
The shortest distance (air line) between Petersburg and Opglabbeek is 4,000.12 mi (6,437.57 km).
How far is Petersburg from Opglabbeek
Petersburg is located in Virginia, United States within 37° 12' 15.48" N -78° 36' 31.32" W (37.2043, -77.3913) coordinates. The local time in Petersburg is 18:52 (04.02.2025)
Opglabbeek is located in Arr. Maaseik, Belgium within 51° 2' 60" N 5° 34' 59.88" E (51.0500, 5.5833) coordinates. The local time in Opglabbeek is 00:52 (05.02.2025)
The calculated flying distance from Opglabbeek to Opglabbeek is 4,000.12 miles which is equal to 6,437.57 km.
Petersburg, Virginia, United States
Related Distances from Petersburg
Opglabbeek, Arr. Maaseik, Belgium