Distance from Petersburg to Raamsdonksveer
The shortest distance (air line) between Petersburg and Raamsdonksveer is 3,955.77 mi (6,366.19 km).
How far is Petersburg from Raamsdonksveer
Petersburg is located in Virginia, United States within 37° 12' 15.48" N -78° 36' 31.32" W (37.2043, -77.3913) coordinates. The local time in Petersburg is 08:34 (01.03.2025)
Raamsdonksveer is located in West-Noord-Brabant, Netherlands within 51° 40' 59.88" N 4° 52' 0.12" E (51.6833, 4.8667) coordinates. The local time in Raamsdonksveer is 14:34 (01.03.2025)
The calculated flying distance from Raamsdonksveer to Raamsdonksveer is 3,955.77 miles which is equal to 6,366.19 km.
Petersburg, Virginia, United States
Related Distances from Petersburg
Raamsdonksveer, West-Noord-Brabant, Netherlands