Distance from Petersburg to Radlje ob Dravi
The shortest distance (air line) between Petersburg and Radlje ob Dravi is 4,526.66 mi (7,284.95 km).
How far is Petersburg from Radlje ob Dravi
Petersburg is located in Virginia, United States within 37° 12' 15.48" N -78° 36' 31.32" W (37.2043, -77.3913) coordinates. The local time in Petersburg is 03:48 (10.03.2025)
Radlje ob Dravi is located in Koroška, Slovenia within 46° 36' 54.72" N 15° 13' 35.04" E (46.6152, 15.2264) coordinates. The local time in Radlje ob Dravi is 09:48 (10.03.2025)
The calculated flying distance from Radlje ob Dravi to Radlje ob Dravi is 4,526.66 miles which is equal to 7,284.95 km.
Petersburg, Virginia, United States
Related Distances from Petersburg
Radlje ob Dravi, Koroška, Slovenia