Distance from Petersburg to Rotselaar
The shortest distance (air line) between Petersburg and Rotselaar is 3,967.08 mi (6,384.40 km).
How far is Petersburg from Rotselaar
Petersburg is located in Virginia, United States within 37° 12' 15.48" N -78° 36' 31.32" W (37.2043, -77.3913) coordinates. The local time in Petersburg is 21:50 (04.02.2025)
Rotselaar is located in Arr. Leuven, Belgium within 50° 57' 3.96" N 4° 42' 38.88" E (50.9511, 4.7108) coordinates. The local time in Rotselaar is 03:50 (05.02.2025)
The calculated flying distance from Rotselaar to Rotselaar is 3,967.08 miles which is equal to 6,384.40 km.
Petersburg, Virginia, United States
Related Distances from Petersburg
Rotselaar, Arr. Leuven, Belgium