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      Distance from Petersburg to San Baudilio de Llobregat

      The shortest distance (air line) between Petersburg and San Baudilio de Llobregat is 4,103.90 mi (6,604.59 km).

      How far is Petersburg from San Baudilio de Llobregat

      Petersburg is located in Virginia, United States within 37° 12' 15.48" N -78° 36' 31.32" W (37.2043, -77.3913) coordinates. The local time in Petersburg is 20:21 (12.03.2025)

      San Baudilio de Llobregat is located in Barcelona, Spain within 41° 20' 44.88" N 2° 2' 30.12" E (41.3458, 2.0417) coordinates. The local time in San Baudilio de Llobregat is 02:21 (13.03.2025)

      The calculated flying distance from San Baudilio de Llobregat to San Baudilio de Llobregat is 4,103.90 miles which is equal to 6,604.59 km.

      Petersburg, Virginia, United States

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      San Baudilio de Llobregat, Barcelona, Spain

      Related Distances to San Baudilio de Llobregat