Distance from Petersburg to San Pietro in Casale
The shortest distance (air line) between Petersburg and San Pietro in Casale is 4,426.88 mi (7,124.38 km).
How far is Petersburg from San Pietro in Casale
Petersburg is located in Virginia, United States within 37° 12' 15.48" N -78° 36' 31.32" W (37.2043, -77.3913) coordinates. The local time in Petersburg is 03:46 (27.02.2025)
San Pietro in Casale is located in Bologna, Italy within 44° 42' 0" N 11° 24' 0" E (44.7000, 11.4000) coordinates. The local time in San Pietro in Casale is 09:46 (27.02.2025)
The calculated flying distance from San Pietro in Casale to San Pietro in Casale is 4,426.88 miles which is equal to 7,124.38 km.
Petersburg, Virginia, United States
Related Distances from Petersburg
San Pietro in Casale, Bologna, Italy