Distance from Petersburg to Sannicolau Mare
The shortest distance (air line) between Petersburg and Sannicolau Mare is 4,767.00 mi (7,671.75 km).
How far is Petersburg from Sannicolau Mare
Petersburg is located in Virginia, United States within 37° 12' 15.48" N -78° 36' 31.32" W (37.2043, -77.3913) coordinates. The local time in Petersburg is 15:05 (06.03.2025)
Sannicolau Mare is located in Timiş, Romania within 46° 3' 48.96" N 20° 36' 45" E (46.0636, 20.6125) coordinates. The local time in Sannicolau Mare is 22:05 (06.03.2025)
The calculated flying distance from Sannicolau Mare to Sannicolau Mare is 4,767.00 miles which is equal to 7,671.75 km.
Petersburg, Virginia, United States
Related Distances from Petersburg
Sannicolau Mare, Timiş, Romania