Distance from Petersburg to Sassenberg
The shortest distance (air line) between Petersburg and Sassenberg is 4,074.50 mi (6,557.27 km).
How far is Petersburg from Sassenberg
Petersburg is located in Virginia, United States within 37° 12' 15.48" N -78° 36' 31.32" W (37.2043, -77.3913) coordinates. The local time in Petersburg is 13:44 (13.02.2025)
Sassenberg is located in Warendorf, Germany within 51° 59' 22.92" N 8° 2' 26.88" E (51.9897, 8.0408) coordinates. The local time in Sassenberg is 19:44 (13.02.2025)
The calculated flying distance from Sassenberg to Sassenberg is 4,074.50 miles which is equal to 6,557.27 km.
Petersburg, Virginia, United States
Related Distances from Petersburg
Sassenberg, Warendorf, Germany