Distance from Petersburg to Schenefeld
The shortest distance (air line) between Petersburg and Schenefeld is 4,101.25 mi (6,600.32 km).
How far is Petersburg from Schenefeld
Petersburg is located in Virginia, United States within 37° 12' 15.48" N -78° 36' 31.32" W (37.2043, -77.3913) coordinates. The local time in Petersburg is 16:47 (13.02.2025)
Schenefeld is located in Pinneberg, Germany within 53° 36' 10.08" N 9° 49' 23.88" E (53.6028, 9.8233) coordinates. The local time in Schenefeld is 22:47 (13.02.2025)
The calculated flying distance from Schenefeld to Schenefeld is 4,101.25 miles which is equal to 6,600.32 km.
Petersburg, Virginia, United States
Related Distances from Petersburg
Schenefeld, Pinneberg, Germany