Distance from Petersburg to Scherpenheuvel
The shortest distance (air line) between Petersburg and Scherpenheuvel is 3,976.31 mi (6,399.25 km).
How far is Petersburg from Scherpenheuvel
Petersburg is located in Virginia, United States within 37° 12' 15.48" N -78° 36' 31.32" W (37.2043, -77.3913) coordinates. The local time in Petersburg is 21:49 (04.02.2025)
Scherpenheuvel is located in Arr. Leuven, Belgium within 51° 0' 37.08" N 4° 58' 22.08" E (51.0103, 4.9728) coordinates. The local time in Scherpenheuvel is 03:49 (05.02.2025)
The calculated flying distance from Scherpenheuvel to Scherpenheuvel is 3,976.31 miles which is equal to 6,399.25 km.
Petersburg, Virginia, United States
Related Distances from Petersburg
Scherpenheuvel, Arr. Leuven, Belgium