Distance from Petersburg to Scherpenzeel
The shortest distance (air line) between Petersburg and Scherpenzeel is 3,970.18 mi (6,389.39 km).
How far is Petersburg from Scherpenzeel
Petersburg is located in Virginia, United States within 37° 12' 15.48" N -78° 36' 31.32" W (37.2043, -77.3913) coordinates. The local time in Petersburg is 08:35 (01.03.2025)
Scherpenzeel is located in Veluwe, Netherlands within 52° 4' 59.88" N 5° 28' 0.12" E (52.0833, 5.4667) coordinates. The local time in Scherpenzeel is 14:35 (01.03.2025)
The calculated flying distance from Scherpenzeel to Scherpenzeel is 3,970.18 miles which is equal to 6,389.39 km.
Petersburg, Virginia, United States
Related Distances from Petersburg
Scherpenzeel, Veluwe, Netherlands