Distance from Petersburg to Seeheim-Jugenheim
The shortest distance (air line) between Petersburg and Seeheim-Jugenheim is 4,158.73 mi (6,692.82 km).
How far is Petersburg from Seeheim-Jugenheim
Petersburg is located in Virginia, United States within 37° 12' 15.48" N -78° 36' 31.32" W (37.2043, -77.3913) coordinates. The local time in Petersburg is 19:12 (13.02.2025)
Seeheim-Jugenheim is located in Darmstadt-Dieburg, Germany within 49° 46' 0.12" N 8° 39' 0" E (49.7667, 8.6500) coordinates. The local time in Seeheim-Jugenheim is 01:12 (14.02.2025)
The calculated flying distance from Seeheim-Jugenheim to Seeheim-Jugenheim is 4,158.73 miles which is equal to 6,692.82 km.
Petersburg, Virginia, United States
Related Distances from Petersburg
Seeheim-Jugenheim, Darmstadt-Dieburg, Germany