Distance from Petersburg to Sint-Andries
The shortest distance (air line) between Petersburg and Sint-Andries is 3,898.89 mi (6,274.66 km).
How far is Petersburg from Sint-Andries
Petersburg is located in Virginia, United States within 37° 12' 15.48" N -78° 36' 31.32" W (37.2043, -77.3913) coordinates. The local time in Petersburg is 21:50 (04.02.2025)
Sint-Andries is located in Arr. Brugge, Belgium within 51° 12' 0" N 3° 10' 59.88" E (51.2000, 3.1833) coordinates. The local time in Sint-Andries is 03:50 (05.02.2025)
The calculated flying distance from Sint-Andries to Sint-Andries is 3,898.89 miles which is equal to 6,274.66 km.
Petersburg, Virginia, United States
Related Distances from Petersburg
Sint-Andries, Arr. Brugge, Belgium